I found out online that the overall dimensions of a regular Cambell's soup can is 4 x 2.625 x 2.625 inches. If we convert this into cm, this would be 10.16 x 6.67 x 6.67 cm.
Therefore, the volume of the can is going to be pi*(radius^2)*height. Radius will be half of the diameter which is 6.67/ 2= 3.34 cm. The volume in cm would be: pi*(3.34^2)*10.16= 356.07 cm^3.
Then I searched online and found out that for Susan's high (5 feet 5 inches, as she mentioned in the class), a road bike should be around 54 cm.
By looking at the picture given of the bike in front of the big soup can, one can see that if you have 2.5 bikes stacked on top of each other in place of one bike in the picture, that would give us the approximate diameter of the big soup can. Therefore, 2.5 times the height of Susan's bike: 2.5* 54 cm= 135 cm is approximate diameter of the can.
Now we can come up with an algebraic equation as follows with the given information:
Let x= height of the big soup can.
diameter of the big soup can= 135 cm
height of the normal soup can= 10.16 cm
diameter of the normal soup can = 6.67 cm
Therefore: (135/ 6.67)* 10.16 = 205.64 cm = x
From this we can find the volume of the big soup can that is:
pi*(67.5^2)*205.64 = 2943506.60 cm^3.
Therefore,
The height of the big soup can= 205.64 cm
The diameter of the big soup can= 135 cm
Volume of the big soup can= 2943506. 60 cm
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